3AV100@41A 發表於 2005-9-9 22:05

[Help]F.4 Maths Question

Who can teach me??

Quadratic Equations
(using any method to solve the question and leave the answer in surd)

√2x^2 - 5x + 2√2 = 0

thx a lot

chrisappear 發表於 2005-9-9 22:15

Multiply both sides with √2,
2x^2 - 5√2x + 4 = 0
then it can be factorized to (2x-√2)(x-2√2)=0
The solutions are obvious.

[ Last edited by chrisappear on 2005-9-9 at 22:22 ]

karenwhy 發表於 2005-9-9 23:30

CK4013 發表於 2005-9-10 15:16

When I see the answer in surd
I will use the follwing Equation:
x=[-b±(b^2-4ac)^0.5]/2a

√2x^2 - 5x + 2√2 = 0

x={[-(-5)±(-5^2-4(√2)(2√2)]/(2)(√2)
=(5±3)/2√2
=8/2√2 or =2/2√2
=2√2 or =√2/2

Actually, this method is not good
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