2.
since AP=BQ=CR
ABCD is a square
so PB=QC
angle PBQ=angle QCR
so triangle PBQ is congruent to triangle QCR
so PQ =QR
so PQR is an isos. triangle |
|
|
|
|
1.
a. Triangle QXY is similar to triangle QPR;
=> angle QXY = angle QPR, thus XY // PR
also, triangle AXY is similar to triangle ABC;
=> angle AXY = angle ABC, thus XY // BC
PR // XY // BC and hence the result. |
|
本班為 北鐵線 列車(經 查寧閣)前往 燒山大馬路
|
|
|
|
Advertisement
Advertisement
Advertisement
Advertisement
Advertisement
|